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4.9x^2+12x=44.1
We move all terms to the left:
4.9x^2+12x-(44.1)=0
We add all the numbers together, and all the variables
4.9x^2+12x-44.1=0
a = 4.9; b = 12; c = -44.1;
Δ = b2-4ac
Δ = 122-4·4.9·(-44.1)
Δ = 1008.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-\sqrt{1008.36}}{2*4.9}=\frac{-12-\sqrt{1008.36}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+\sqrt{1008.36}}{2*4.9}=\frac{-12+\sqrt{1008.36}}{9.8} $
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